1/y^-5=32

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Solution for 1/y^-5=32 equation: 



1/y^-5=32

We move all terms to the left:

1/y^-5-(32)=0



Domain of the equation: y^!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

1/y^-37=0

We multiply all the terms by the denominator


-37*y^+1=0

We add all the numbers together, and all the variables

-37y+1=0

We move all terms containing y to the left, all other terms to the right

-37y=-1

y=-1/-37

y=1/37

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